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CGP EDU Academic Team
Published on: September 12, 2026
One gm mol of a diatomic gas $(\gamma = 1.4)$ is compressed adiabatically so that its temperature rises from $27^\circ C$ to $127^\circ \mathrm{C}$ . The work done will be
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A
$W = \frac{R}{\gamma - 1} (T_1 - T_2)$ $= \frac{8.31 \times \{(273 + 27) - (273 + 127)\}}{1.4 - 1} = -2077.5 \text{ joules}$
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